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The compound sodium thiosulfate pentahydrate, Na2S2O3 • 5H2O
is important commercially to the photography business as
“hypo,” because it has the ability to dissolve unreacted silver salts from photographic film during development. Sodium thio-
sulfate pentahydrate can be produced by boiling elemental sulfur
in an aqueous solution of sodium sulfite.
Sg(s) + Na2SO3(aq) + H2O(l) → Na2S2O3.5H2O(s)
(unbalanced) What is the theoretical yield of sodium thiosulfate pentahydrate when 3.25 g of sulfur is boiled with 13.1 g of sodium sulfite? Sodium thiosulfate pentahydrate is a very soluble in water. What is the percent yield of the synthesis if a student doing this experiment is able to isolate (collect) only 5.26 g of the product

Sagot :

pstnonsonjoku

The theoretical yield is 204.4 g while the percent yield is 2.57%.

What is theoretical yield?

Theoretical yield is the amount of product obtained based on the stoichiometry of the reaction.

S8(s) + 8 Na2SO3(aq) + 40 H2O(l) --->8 Na2S2O3·5 H2O(s)

Number of moles of sulfur =  3.25 g /8(32) = 0.013 moles

Number of moles of sodium sulfite =  13.1 g/126 g/mol = 0.103 moles

Since 1 moles of sulfur reacts with 8 moles of sodium sulfite

0.013 moles reacts with 0.013 moles ×  8 moles /1 mole = 0.104 moles

There is not enough sodium sulfite hence it is the limiting reactant.

1 mole of sodium sulfite yields 8 moles of product

0.103 moles of sodium sulfite yields  0.103 moles × 8 moles /1 mole = 0.824 moles

Mass of product = 0.824 moles × 248 g/mol = 204.4 g

percent yield =  5.26 g /204.4 g × 100/1

= 2.57%

Learn more about percent yield: https://brainly.com/question/2506978

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