Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

The width of a rectangle is 8
inches more than the length.
The perimeter is 32.


Sagot :

Answer:

Width: 12 inches

Length: 4 inches

Step-by-step explanation:

To find the width and length, we can solve this algebraically while using the equation [tex]2(x+x+8)=32[/tex]

Step 1: Simplify both sides of the equation.

  • [tex]2(2x+8)=32[/tex]
  • [tex]4x + 16 = 32[/tex]

Step 2: Subtract 16 from both sides.

  • [tex]4x+16-16=32-16[/tex]
  • [tex]4x = 16[/tex]

Step 3: Divide both sides by 4.

  • [tex]4x/4 = 16/4[/tex]
  • [tex]x = 4[/tex]

Since x (4) is the length, the width is 12 inches.

  • [tex]2(4+12)[/tex]
  • [tex]2(16)[/tex]
  • [tex]32[/tex]

Therefore, the width is 12 inches and the length is 4 inches.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

  ~ ren ⚘

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.