Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
Here is my written solution, I hope it helps you :)
Alternatively to this you could use the equation of 7500 x 1.06^t and use trial and error by replacing the value of t until you go beyond £10000.
Alternatively to this you could use the equation of 7500 x 1.06^t and use trial and error by replacing the value of t until you go beyond £10000.
Answer: 5 years
==========================================
Work Shown:
[tex]A = P*(1+r/n)^{n*t}\\\\10,000 = 7500*(1+0.06/1)^{1*t}\\\\10,000/7500 = (1.06)^{t}\\\\1.33333 \approx (1.06)^{t}\\\\\text{Log}(1.33333) \approx \text{Log}\left((1.06)^{t}\right)\\\\\text{Log}(1.33333) \approx t*\text{Log}(1.06)\\\\t \approx \frac{\text{Log}(1.33333)}{\text{Log}(1.06)}\\\\t \approx 4.937[/tex]
The first equation shown is the compound interest formula. I'm assuming that the bank is compounding annually (which means n = 1).
Whenever we have an exponent we want to solve for, we'll involve logs. A good phrase to remember is "If the exponent is in the trees, then log it down".
It takes approximately t = 4.937 years for the £7500 to become £10,000.
Round up to the nearest year to get t = 5 so we ensure that Brian has more than £10,000.
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.