Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
Answers:
- slower train = 139 km per hour
- faster train = 159 km per hour
=================================================
Explanation:
x = rate of the slower train
x+20 = rate of the faster train
rates are in km per hour, abbreviated as kph
The train traveling at x kph will travel 5x km after 5 hours.
Use this formula
distance = rate*time
Using that same formula, the faster train travels 5(x+20) = 5x+100 kilometers in 5 hours.
The two distances must add to 1490 if we want the trains to pass by each other. Assume that the trains are traveling on parallel side-by-side tracks.
--------------------------
So,
(slower train distance) + (faster train distance) = 1490
(5x) + (5x+100) = 1490
10x+100 = 1490
10x = 1490-100
10x = 1390
x = 1390/10
x = 139
The slower train moves at a rate of 139 km per hour.
x+20 = 139+20 = 159
The faster train moves at a speed of 159 km per hour.
--------------------------
Check:
The slower train travels 139 kph and travels for 5 hours, so it covers a distance of 139*5 = 695 km
The faster train has a speed of 159 kph and travels for 5 hours, so it covers 159*5 = 795 km
Total distance = 695+795 = 1490
The answers are confirmed.
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.