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Given a side of a Square is 3cm. Find area and perimeter of the square. ​

Sagot :

Answer:

Area: 9cm²

Perimeter: 12 cm

Explanation:

Area is length x width

It's a square so length and width are the same

3 times 3 is 9

And to find the perimeter you just add the side lengths

Squares have 4 sides and the given side length is 3 so 3x4 OR 3+3+3+3 is how you get the perimeter.

[tex] \star \pink{\frak{Given}}[/tex]

[tex] \\ \\ [/tex]

  • Side of a Square = 3cm

[tex] \\ \\ [/tex]

[tex] \star \blue{\frak{To \: find :}}[/tex]

[tex] \\ \\ [/tex]

  • Area of a Square

  • Perimeter of a Square

[tex] \\ \\ [/tex]

[tex] \star \orange{\frak{Solution :}}[/tex]

[tex] \\ \\ [/tex]

There are two parts in this question. In first part we have to find area and in second part we have to find perimeter of a Square.

[tex] \\ \\ [/tex]

[tex] \green{ \text{part \: 1}}[/tex]

[tex] \\ [/tex]

To find Area of a Square :

we know:

[tex]\bigstar \boxed{ \tt{Area \: of \: a \: Square = }{ \tt{side}^{2} }}[/tex]

[tex] \\[/tex]

So :

[tex] \\ [/tex]

[tex]\dashrightarrow \sf{Area \: of \: a \: Square = }{ \sf{side}^{2} }[/tex]

[tex] \\ \\ [/tex]

[tex]\dashrightarrow \sf{Area \: of \: a \: Square = }{ \sf{3}^{2} }[/tex]

[tex] \\ \\ [/tex]

[tex]\dashrightarrow \sf{Area \: of \: a \: Square = }{ \sf3 \times 3}[/tex]

[tex] \\ \\ [/tex]

[tex]\dashrightarrow \sf{Area \: of \: a \: Square = }{ \sf9cm {}^{2} }[/tex]

[tex] \\ \\ [/tex]

[tex] \therefore \underline \textsf{ \textbf{Area \: of \: a \: square \: = \red{9 {cm} }}} \red{ \bf^{2}}[/tex]

[tex] \\ \\ [/tex]

[tex] \green{ \text{part \: 2}}[/tex]

[tex] \\ \\ [/tex]

To find perimeter of square :

[tex] \\ \\ [/tex]

[tex]\bigstar \boxed{ \tt{Perimeter \: of \: a \: Square = }{ \tt4 \times {side}}}[/tex]

[tex] \\ \\ [/tex]

So:

[tex] \\ \\ [/tex]

[tex]\dashrightarrow \sf{Perimeter \: of \: a \: Square = }{ \sf4 \times side} \\ [/tex]

[tex] \\ \\ [/tex]

[tex]\dashrightarrow \sf{Perimeter \: of \: a \: Square = }{ \sf4 \times 3} \\ [/tex]

[tex] \\ \\ [/tex]

[tex]\dashrightarrow \sf{Perimeter \: of \: a \: Square = }{ \sf12cm} \\ [/tex]

[tex] \\ \\ [/tex]

[tex] \therefore \underline{ \textsf{ \textbf{perimeter \: of \: a \: square \: = \red{12cm}}}}[/tex]