Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

What is the value of x?



Enter your answer in the box.

x =


What Is The Value Of X Enter Your Answer In The Box X class=

Sagot :

[tex] \star \blue{ \frak{To \: find :}}[/tex]

[tex] \\ \\ [/tex]

  • value of x

[tex] \\ \\ [/tex]

[tex] \star \blue{ \frak{solution:}}[/tex]

[tex] \\ \\ [/tex]

So to find value of x , we have to apply Linear Pair.

[tex] \\ \\ [/tex]

Equation formed:

[tex] \\ \\ [/tex]

[tex] \bigstar \boxed{ \tt(10x - 20) \degree + (6x + 8)\degree = 180 \degree} \\ [/tex]

[tex] \\ \\ [/tex]

Step by step expansion:

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf(10x - 20) \degree + (6x + 8)\degree = 180 \degree \\[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf10x - 20 \degree + 6x + 8\degree = 180 \degree \\[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf10x +6x- 20 \degree + 8\degree = 180 \degree \\[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf16x- 20 \degree + 8\degree = 180 \degree \\[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf16x- 12\degree = 180 \degree \\[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf16x = 180 \degree + 12\degree\\[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf16x =192\degree\\[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf \: x = \frac{192\degree}{16\degree} \\[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf \: x = 12 \degree[/tex]

[tex] \\ \\ [/tex]

[tex]\therefore \underline {\textsf{\textbf{Value of x is \red{12\degree}}}}[/tex]

Step-by-step explanation:

Linear Pairs of Angles: If a ray stands on a line, then the two adjacent angles so formed is 180° or sum of the angles forming a linear pair is 180°.

Now, from figure:

Given angles are on the straight line

They are linear pair

(10x - 20)° + (6x + 8)° = 180°

Open all the brackets on LHS.

⇛10x - 20° + 6x + 8° = 180°

⇛10x° + 6x - 20 + 8° = 180°

Add and subtract the variables and Constants on LHS.

⇛16x - 12° = 180°

Shift the number -12 from LHS to RHS, changing it's sign.

⇛16x = 180° + 12°

Add the numbers on RHS.

⇛16x = 192°

Shift the number 16 from LHS to RHS, changing it's sign.

⇛x = 192°/16

Simplify the fraction on RHS to get the final value of x.

⇛x = {(192÷2)/(16÷2)}

= (96/8)

= {(96÷2)/(8÷2)}

= (48/4)

= {(48÷2)/(4÷2)}

= (24/2)

= {(24÷2)/(2÷2)} = 12/1

Therefore, x = 12

Answer: Hence, the value of x is 12.

Explore More:

Now,

Finding each angle by substitute the value of x.

Angle (10x-20)° = (10*12-20)° = (120-10)° = (100)° = 100°

Angle (6x+8)° = (6*12+8)° = (72 + 8)° = (80)° = 80°

Verification:

Check whether the value of x is true or false. By substituting the value of x in equation.

(10x-20)° + (6x + 8)° = 180°

⇛(10*12-20)° + (6*12 + 8)° = 180°

⇛(120 - 20)° + (72 + 8)° = 180°

⇛(100)° + (80)° = 180°

⇛100° + 80° = 180°

⇛180° = 180°

LHS = RHS, is true for x = 12.

Hence, verified.

Please let me know if you have any other questions.