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Consider the following reversible reaction.

Upper H subscript 2 upper O (g) double-headed arrow 2 upper H subscript 2 (g) plus upper O subscript 2 (g).

What is the equilibrium constant expression for the given system?
k subscript e q equals StartFraction StartBracket upper H subscript 2 upper O EndBracket over StartBracket upper H subscript 2 EndBracket StartBracket upper O subscript 2 EndBracket EndFraction.
k subscript e q equals StartFraction StartBracket upper H subscript 2 upper O EndBracket superscript 2 over StartBracket upper H subscript 2 EndBracket superscript 2 StartBracket upper O subscript 2 EndBracket EndFraction.
K subscript e q equals StartFraction StartBracket upper H subscript 2 EndBracket superscript 2 StartBracket upper O subscript 2 EndBracket over StartBracket upper H subscript 2 upper O EndBracket EndFraction.
K subscript e q equals StartFraction StartBracket upper H subscript 2 EndBracket superscript 2 StartBracket upper O subscript 2 EndBracket over StartBracket upper H subscript 2 upper O EndBracket superscript 2 EndFraction.


Sagot :

The equilibrium constant for the reaction is:

K subscript eq equals StartFraction StartBracket upper H subscript 2 EndBracket superscript 2 StartBracket upper O subscript 2 EndBracket over StartBracket upper H subscript 2 upper O EndBracket superscript 2 EndFraction.

What is equilibrium constant?

The equilibrium constant (Kₑq) for a given reaction is simply defined as the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient.

For example, the equilibrium constant Kₑq for the reaction below is given as

2A <=> B

Kₑq = [B]/[A]²

How to determine the equilibrium constant

  • 2H₂O(g) <=> 2H₂(g) + O₂(g)
  • Equilibrium constant (Kₑq) =?

Kₑq = [H₂]²[O₂] / [H₂O]²

K subscript eq equals StartFraction StartBracket upper H subscript 2 EndBracket superscript 2 StartBracket upper O subscript 2 EndBracket over StartBracket upper H subscript 2 upper O EndBracket superscript 2 EndFraction.

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