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Solve for x in a right triangle (show work)

Solve For X In A Right Triangle Show Work class=

Sagot :

Starrysoul100

[tex]\bold{\huge{\pink{\underline{Solution}}}}[/tex]

[tex]\bold{\underline{Given :-}}[/tex]

  • We have given two sides of the triangle that is 10cm height and 22cm base

[tex]\bold{\underline{To\: Find :-}}[/tex]

  • We have to find the value of x°

[tex]\bold{\underline{Let's\: Begin :-:-}}[/tex]

Here, we will use the concept of trigonometric ratios that is tan Φ , sinΦ , cos Φ etc.

[tex]\bold{ We\: know \: that, }[/tex]

[tex]\bold { Sin Φ = }{\bold{\frac{Perpendicular}{Hypotenuse}}}[/tex]

[tex]\bold{ Cos Φ = }{\bold {\frac{Base}{Hypotenuse}}}[/tex]

[tex]\bold{ tan Φ = }{\bold{\frac{Perpendicular}{Base}}}[/tex]

Here, we have Perndicular height and base of the given triangle, so we will use tan Φ as a reference for finding the value of x°

[tex]\sf{ tan Φ = }{\sf{\frac{10}{22}}}[/tex]

[tex]\sf{ tan Φ = }{\sf{\frac{5}{11}}}[/tex]

[tex]\sf{ tan Φ = 0.45}[/tex]

[tex]\sf{ tan x° = 27° }[/tex]

[tex]\sf{ Hence, \: The\: value \:of\: x°\: is\: 27°}[/tex]

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