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How many grams of copper metal are required to react with 4.00 grams of silver
nitrate to produce copper (II) nitrate?

Sagot :

fieryanswererft

Answer:

0.753 grams of copper metal are required to react with 4.00 grams of silver nitrate to produce copper (II) nitrate

Explanation:

mass = moles * Mr

                      Equation of this reaction:

          Cu(s) + 2AgNO₃(aq) → Cu(NO₃)₂(aq) + 2Ag(s)

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Find moles of silver nitrate:

4 = moles * 170

→ [tex]\frac{2}{85}[/tex] moles

  • Here we "2" molar ratio before silver nitrate and "1" before copper metal, so copper metal has half the moles of silver nitrate. copper metal has  [tex]\frac{2}{85}[/tex] ÷ 2 =  [tex]\frac{1}{85}[/tex] moles

so find the mass of copper metal:

mass =  [tex]\frac{1}{85}[/tex] * 64

mass of copper is 0.753 grams.

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