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Sagot :
Molar mass of KClO3
[tex]\\ \tt\hookrightarrow 39+35+3(16)[/tex]
[tex]\\ \tt\hookrightarrow 74+48[/tex]
[tex]\\ \tt\hookrightarrow 122g/mol[/tex]
Now
[tex]\\ \tt\hookrightarrow No\:of\:moles=\dfrac{Given\:mass}{Molar\:mass}[/tex]
[tex]\\ \tt\hookrightarrow No\:of\:moles=\dfrac{5}{122}[/tex]
[tex]\\ \tt\hookrightarrow No\:of\:moles=0.04mol[/tex]
1. Calculate the molar mass of KClO3: 39.098+ 35.453 + 3(16) = 122.551 g KClO3
2. 5gKClO3 x 1mol KClO3/ 122.551g KClO3 = 0.041mol of KClO3
2. 5gKClO3 x 1mol KClO3/ 122.551g KClO3 = 0.041mol of KClO3
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