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A package is dropped from a helicopter moving upward at 15 m/s. If it takes 16.0 s before the package strikes the ground, how high above the ground was the package when it was released if air resistance is negligible?

Sagot :

PreetKumarSangdot

We have for the velocity of package v= 20 - 9.8t and distance from the ground y = h + 20t - 4.9t2.

We have y = 0 and t = 18.0 s we have h = 4.9·182  - 20·18 = 1227.6 m.

Velocity at landing v = 20 - 9.8·18 = - 156.4 m/s

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