Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

200.0 mL of a 0.845 M solution of KCl is diluted to 600.0 mL. What is the new concentration of the solution?

Sagot :

  • M be molar concentration
  • V be volume

So

  • M1=0.845M
  • V1=200mL=0.2L
  • V2=0.6L
  • M2=?

[tex]\\ \tt\rightarrowtail M1V1=M2V2[/tex]

[tex]\\ \tt\rightarrowtail 0.845(0.2)=0.6M2[/tex]

[tex]\\ \tt\rightarrowtail 0.169=0.6M2[/tex]

[tex]\\ \tt\rightarrowtail M2=0.281M[/tex]

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.