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200.0 mL of a 0.845 M solution of KCl is diluted to 600.0 mL. What is the new concentration of the solution?

Sagot :

  • M be molar concentration
  • V be volume

So

  • M1=0.845M
  • V1=200mL=0.2L
  • V2=0.6L
  • M2=?

[tex]\\ \tt\rightarrowtail M1V1=M2V2[/tex]

[tex]\\ \tt\rightarrowtail 0.845(0.2)=0.6M2[/tex]

[tex]\\ \tt\rightarrowtail 0.169=0.6M2[/tex]

[tex]\\ \tt\rightarrowtail M2=0.281M[/tex]

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