Answered

Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Theoretically, what volume of hydrogen gas at 27°c and 680 torr is produced in the reaction of 15. 0 g al metal with excess hydrochloric acid to produce alcl_{3} and h_{2} (hint: you may want to write and balance an equation first)?.

Sagot :

CintiaSalazar

Taking into account the reaction stoichiometry and the ideal gas law, 22.84 L of hydrogen gas at 27°c and 680 torr is produced in the reaction of 15 g Al metal with excess hydrochloric acid to produce AlCl₃ and H₂.

Reaction stoichiometry

In first place, the balanced reaction is:

2 Al + 6 HCl → 2 AlCl₃ + 3 H₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Al: 2 moles
  • HCl: 6 moles
  • AlCl₃: 2 mole
  • H₂: 3 moles

The molar mass of the compounds is:

  • Al: 27 g/mole
  • HCl: 36.45 g/mole
  • AlCl₃: 133.35 g/mole
  • H₂: 2 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Al: 2 moles× 27 g/mole= 54 grams
  • HCl: 6 moles× 36.45 g/mole= 218.7 grams
  • AlCl₃: 2 moles× 133.35 g/mole= 266.7 grams
  • H₂: 3 moles× 2 g/mole= 6 grams

Number of moles of H₂ produced

The following rule of three can be applied: If by stoichiometry of the reaction 54 grams of Al produces 3 moles of H₂, 15 grams of Al produces how many moles of H₂?

[tex]moles of H_{2} =\frac{15 grams of Alx3 moles of H_{2} }{54 grams of Al}[/tex]

moles of H₂= 0.83 moles

Ideal gas law

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of gases:

P×V = n×R×T

Volume of hydrogen gas

In this case, you know:

  • P= 680 torr
  • V= ?
  • n=0.83 moles
  • R= 62.364 [tex]\frac{torr L}{mol K}[/tex]
  • T= 27 C= 300 K (being 0 C= 273 K)

Replacing in the ideal gas:

680 torr×V = 0.83 moles×62.364 [tex]\frac{torr L}{mol K}[/tex]×300 K

Solving:

V= (0.83 moles×62.364 [tex]\frac{torr L}{mol K}[/tex]×300 K)÷ 680 torr

V= 22.84 L

Finally, 22.84 L of hydrogen gas at 27°c and 680 torr is produced in the reaction of 15 g Al metal with excess hydrochloric acid to produce AlCl₃ and H₂.

Learn more about

the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

ideal gas law:

https://brainly.com/question/4147359?referrer=searchResults

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.