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Find the area of the irregular figure. plssss

Find The Area Of The Irregular Figure Plssss class=

Sagot :

Starrysoul100

[tex]\bold{\huge{\green{\underline{ Solution }}}}[/tex]

[tex]\bold{\underline{Let's \: Begin :- }}[/tex]

Here, we have given :-

  • A rectangle having dimensions 14cm , 21 cm and 12cm
  • A triangle having dimensions 16cm and x

[tex]\bold{\underline{ We\:know\:that :- }}[/tex]

[tex]\sf{\red{ Area of rectangle = L × B }}[/tex]

We know that,

The opposite sides of rectangle are equal so from above figure we can conclude that the length and breath of the rectangle are also equal that is 14cm and 21 cm

Subsitute the required values in the above formula :-

[tex]\sf{ Area \:of\: rectangle = 14 × 21}[/tex]

[tex]\sf{ = 294cm²}[/tex]

[tex]\sf{ Thus, \: the \:area\:of \: rectangle = 294cm²}[/tex]

[tex]\bold{\underline{ Now }}[/tex]

We have another figure that is triangle and we have dimensions 16cm and x. x is used to denote the height of the triangle

[tex]\sf{\underline{ For\: height }}[/tex]

[tex]\sf{\underline{ = 21 - 12 }}[/tex]

[tex]\sf{\underline{ = 9 }}[/tex]

Therefore,

[tex]\sf{ Area \:of\: triangle = 1/2 × B × H}[/tex]

[tex]\sf{ Area \:of\: triangle = 1/2 × 16 × 9}[/tex]

[tex]\sf{ Area \:of\: triangle = 8 × 9}[/tex]

[tex]\sf{ Area \:of\: triangle = 72 cm²}[/tex]

[tex]\sf{ Thus, \: the \:area\:of \: triangle = 72 cm²}[/tex]

[tex]\bold{\underline{ Now }}[/tex]

[tex]\sf{\underline{Total \: area\: of\:irregular \: figure}}[/tex]

[tex]\sf{ = 294 + 72}[/tex]

[tex]\sf{ = 366 cm²}[/tex]

[tex]\sf{\red{Hence, \:The\: total\: area \:is\: 366 cm²}}[/tex]

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