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Given that the antiderivative of f of x equals 1 divided by x is F(x) = Ln|x| + C, evaluate the integral from 1 to 2 of the 1 divided by x, dx.

Sagot :

LammettHash

By the fundamental theorem of calculus,

[tex]\displaystyle \int_1^2 \frac1x \, dx = F(2) - F(1) = \ln|2| - \ln|1| = \boxed{\ln(2)}[/tex]

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