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Find the zeros of the function: f(x)=-2x(x+7)+10x+70

Sagot :

Answer:

[tex]x=\displaystyle\frac{3\pm\sqrt{569}}{4}[/tex]

Step-by-step explanation:

Hi there!

[tex]f(x) = -2x(x+7)+10x+70\\f(x) = -2x^2-7x+10x+70\\f(x) = -2x^2+3x+70[/tex]

We can solve this by using the quadratic formula, which states:

[tex]x=\displaystyle\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex] where [tex]f(x)=ax^2+bx+c[/tex]

Plug in the values a, b and c:

[tex]x=\displaystyle\frac{-3\pm\sqrt{3^2-4(-2)(70)}}{2(-2)}\\\\x=\displaystyle\frac{-3\pm\sqrt{9+560}}{-4}\\\\x=\displaystyle\frac{-3\pm\sqrt{569}}{-4}\\\\x=\displaystyle\frac{3\pm\sqrt{569}}{4}[/tex]

I hope this helps!