Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

A 1. 5 kg block is pulled across a horizontal surface that has a coefficient of kinetic friction of 0. 60. A. What is the force of friction exerted by the surface on the block?.

Sagot :

LammettHash

Perpendicular to the surface, the net force on the block is

∑ F = F[normal] - (1.5 kg) g = 0

so that the normal force exerted by the surface on the block is

F[normal] = (1.5 kg) g = 14.7 N

Then the magnitude of kinetic friciton felt by the block is

0.60 (14.7 N) = 8.82 N ≈ 8.8 N

We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.