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Sagot :
According to the null hypothesis, the test statistic of the proportion is of z = 120.1.
What is the null hypothesis?
The claim is that the rate of nausea is greater than the 6% rate experienced by flu patients given a placebo. At the null hypothesis, we consider the claim as false, hence the null hypothesis is:
[tex]H_0: p \leq 0.06[/tex]
What is the test statistic?
The test statistic is given by:
[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
In which:
- [tex]\overline{p}[/tex] is the sample proportion.
- p is the proportion tested at the null hypothesis.
- n is the sample size.
In this problem, the parameters are:
[tex]p = 0.06, n = 724, \overline{p} = \frac{72}{724} = 0.0994[/tex]
Hence, the test statistic is given by:
[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
[tex]z = \frac{0.0994 - 0.06}{\sqrt{\frac{0.06(0.94)}{724}}}[/tex]
[tex]z = 120.1[/tex]
You can learn more about test statistic at https://brainly.com/question/16313918
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