Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
Using conditional probability, it is found that there is a 0.052 = 5.2% probability that a randomly chosen U. S. President is left-handed and a democrat.
What is Conditional Probability?
Conditional probability is the probability of one event happening, considering a previous event. The formula is:
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
- P(B|A) is the probability of event B happening, given that A happened.
- [tex]P(A \cap B)[/tex] is the probability of both A and B happening.
- P(A) is the probability of A happening.
In this problem, the events are:
- Event A: President is left-handed.
- Event B: President is a democrat.
Researching the problem on the internet, it is found that:
- 40% of the presidents were left-handed, hence P(A) = 0.4.
- If a president is left-handed, there is a 13% chance that the president is a Democrat, hence P(B|A) = 0.13.
Then:
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
[tex]0.13 = \frac{P(A \cap B)}{0.4}[/tex]
[tex]P(A \cap B) = 0.13(0.4)[/tex]
[tex]P(A \cap B) = 0.052[/tex]
0.052 = 5.2% probability that a randomly chosen U. S. President is left-handed and a democrat.
You can learn more about conditional probability at https://brainly.com/question/15536019
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.
