Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

The power P that must be delivered by a car's engine varies directly as the distance dthat the car moves and inversely as the time t required to move that distance. To move the car 1,400ft in 70s, the engine must deliver 112kilowatts (kW) of power. Find the distance (in feet) the car moves when 148kW of power is delivered for 90s. Enter the answer as an integer. Round to the nearest whole unit, if needed.

Sagot :

Answer:

P ∝ d

P ∝ 1/t

Using this information, we can establish a formula:

P = Kd/t  , where K is some constant

We need to determine that constant using the initial conditions.

d = 2100 ft

t = 70 s

P = 180 KW

K = Pt/d

K = [(180 kW)(70s)] / 2100 ft

K = 6 kW s / ft

We can now find the distance of the car when P = 204 kW and t = 90s

P = Kd/t

d = Pt/K

d = [(204 kW)(90 s)] / (6 kWs /ft)

d = 3060 ft

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.