Answered

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a
Prove: The square of a number that is
two more than a multiple of 3 is one more
than a multiple of 3.

(3n + 2)^2 = [? ]

A Prove The Square Of A Number That Is Two More Than A Multiple Of 3 Is One More Than A Multiple Of 3 3n 22 class=

Sagot :

Answer:

Step-by-step explanation:

[tex](3n+2)^{2} = (3n+2)(3n+2)[/tex]

[tex]9n^{2} +12n+4[/tex] - I expanded the above brackets

[tex]9n^{2} +12n+3+1[/tex]  - I separated the 1 from 4 to make 3+1

[tex]3(3n^{2} +4n+1)+1[/tex] - I took out a factor of 3

= 1 more than a multiple of 3

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