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What is the equation in standard form of the line that passes through the point (6,-1) and is
parallel to the line represented by 8x + 3y = 15?
A 8x + 3y = -45
B 8x - 3y = -51
C 8x + 3y = 45
D 8x - 3y = 51

What Is The Equation In Standard Form Of The Line That Passes Through The Point 61 And Is Parallel To The Line Represented By 8x 3y 15 A 8x 3y 45 B 8x 3y 51 C 8 class=

Sagot :

dmr217dmr

Answer:

C; 8x+3y= 45  

Step-by-step explanation:

The process is really long so here we go...

8x+3y=15 is the equation and we want to bring it to slope intercept form so that we can know what the slope is.

(8x+3y=15) -8x = (3y=-8x+15) /3 = y= -8/3x +5

We now know that the slope of the equation is -8/3x, and since we are trying to find out a line parallel to the that equation we can use the same slope in the equation: y+y1=m(x+x1)

Which would be: y-1=-8/3(x+6)

then: y-1=-8/3x-16

then: y= 8/3x+15

We're not done yet because we have to simplify it to standard form so we can subtract 8/3x so that it can join the y's side, and we would have the multiply the whole equation by -3 so that x wouldn't be a fraction, which results it not being in standard form. That leaves the final answer, 8x+3y=45

The equation in standard form of the line that passes through the point (6, -1) and is parallel to the line represented by  8x + 3y = 15 is 8x + 3y = 45

Equation in standard form

Ax + Bx = C

where

  • A, B and C are constant

Therefore, using slope intercept form

y = mx + b

where

m = slope

b = y-intercept

8x + 3y = 15

3y = -8x + 15

y = -8 / 3 x + 5

slope = - 8 / 3

It passes through (6, -1)

let's find b

-1 = - 8 / 3 (6) + b

-1 = -48 / 3 + b

-1  = -16 + b

b = -1 + 16

b = 15

Therefore,

y = - 8 / 3 x + 15

8 / 3 x  + y = 15

8x + 3y = 45

learn more on standard form equation here: https://brainly.com/question/9662298

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