This question involves the concepts of electric field strength and distance.
The strength of the electric field is "215760 N/C".
The electric field strength due to a charge is given by the following formula:
[tex]E = \frac{kq}{r^2}[/tex]
where,
Therefore,
[tex]E=\frac{(8.99\ x\ 10^9\ N.m^2/C^2)(6\ x\ 10^{-6}\ C)}{(0.5\ m)^2}[/tex]
E = 215760 N/C
Learn more about electric field strength here:
https://brainly.com/question/4264413
This question involves the concepts of electric field strength and distance.The strength of the electric field is "215760 N/C".
The electric field strength due to a charge is given by the following formula:
[tex]E=\dfrac{kq}{r^2}[/tex]
where,
E = Electric Field Strength = ?
k = Colomb's constant = 8.99 x 10⁹ N.m²/C²
q = magnitude of charge = 6 μC = 6 x 10⁻⁶ C
r = distance = 0.5 m
Therefore, putting the values in the formula;
[tex]E=\dfrac{(8.99\times 10^9)(6\times 10^{-6})}{0.5}[/tex]
E = 215760 N/C
Thus the strength of the electric field is "215760 N/C".
Learn more about electric field strength here:
brainly.com/question/4264413
