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Sagot :
The containers that have equal pressures are Container A and Container C
Gas Laws
From the question, we are to determine which containers have equal pressures.
Using the ideal gas law equation, we will determine the containers that have equal pressures.
From the ideal gas equation, we have
PV = nRT
Where,
P is the pressure
V is the volume
n is the number of moles
R is the gas constant
and T is the temperature
Then,
[tex]P = \frac{nRT}{V}[/tex]
- Container A
n = 0.5 mole
V = 11.2 L
[tex]P = \frac{0.5 \times RT}{11.2}[/tex]
P = 0.04464RT
- Container B
n = 2 moles
V = 22.4 L
[tex]P = \frac{2 \times RT}{22.4}[/tex]
P = 0.0892857RT
- Container C
n = 1 mole
V = 22.4 L
[tex]P = \frac{1\times RT}{22.4}[/tex]
P = 0.04464RT
- Container D
n = 2 mole
V = 11.2 L
[tex]P = \frac{2 \times RT}{11.2}[/tex]
P = 0.17857RT
From above, we can observe that Container A and Container C have equal pressures. P = 0.04464RT
Hence, the containers that have equal pressures are Container A and Container C.
Learn more on Gas laws here: https://brainly.com/question/25736513
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