Answered

Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

For parts of the free-response question that require calculations, clearly show the method used and the steps involved in arriving at your answers. You must show your work to receive credit for your answer. Examples and equations may be included in your answers where appropriate.
PbI2(s)⇄Pb2+(aq)+2I−(aq)Ksp=7×10−9
The dissolution of PbI2(s) is represented above.
Write a mathematical expression that can be used to determine the value of S, the molar solubility of PbI2(s). (Do not do any numerical calculations.)

Sagot :

pstnonsonjoku

The molar solubility of lead II iodide is 1.21 × 10^-3 M.

What is solubility product?

The term solubility product refers to the equilibrium constant that shows the extent to which a substance is dissolved in water. For the dissolution of lead II iodide we can write;

PbI2(s) ⇄ Pb^2+(aq) + 2I^-(aq)

Hence;

Ksp = [x] [2x]^2 = 4x^3

x = ∛Ksp/4

x  = ∛7 × 10^-9/4

x = 1.21 × 10^-3 M

Learn more about solubility product: https://brainly.com/question/857770

We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We hope this was helpful. Please come back whenever you need more information or answers to your queries. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.