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A force of 20 N is applied to accelerate a 9.0 kg wagon at 2.0 m/s^2 along the sidewalk. How large is the force of friction?

Draw and label the free body diagram!


Sagot :

Explanation:

[tex]Σf = ma[/tex]

This means the sum of all forces acting on an object = mass times accleration so first, let find the ma.

The mass is 9 kg and the acclereation is 2.0 m/s^2.

[tex]Σf = 9(2)[/tex]

which equals

18 N.

So the mass times accleration equal 18 N.

So now what are forces acting on the box?

Since the box isn't levitationg nor falling, the vertical forces, mg and normal force cancel out to 0. so we only have horinzontial forces.

The push force is 20 N and the friction force is considered negative so we have

[tex]p - f = 18[/tex]

p is 20 so we get

[tex]20 - f = 18[/tex]

[tex] - f = - 2[/tex]

[tex]f = 2[/tex]

So the friction force is 2 N

p is the push force and that us

For the free body diagram, draw a square, and draw arrows from the center of the square in all 4 ways.

Make sure the vertical arrows are equal in length to show they cancel out.

The right horinzontial arrow should be 20 N and the left arrow should be 2 N