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Sagot :
Based on the information given, it has been computed that the activation energy will be 105.8Kj.
How to calculate activition energy
From the information given,
T1 = 25 + 273 = 298K
T2 = 35 + 273 = 308J
R = 8.314J/mol
K2/K1 = 4
Therefore,
log(4) = E/(2.303 × 8.314) × [10/(298 × 308)]
= (0.602 × 2.303 × 8.314 × 298 × 308) / 10
= 105.8KJ
Therefore, the activation energy is 105.8KJ.
Learn more about activation energy on:
https://brainly.com/question/1380484
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