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how many moles are present in 356.4 g of NiBr3

Sagot :

paulnguyen1209

1.194 mol

(remember to use sig figs!)

1.19 moles are present in 356.4 g of NiBr3

What are moles?

A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Molar mass of [tex]NiBr_3[/tex]

58.6934 + 3 x 79.904 = 298.4054

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]Moles = \frac{356.4 g}{298.4054}[/tex]

Moles =1.19434836 =1.19 moles

Hence, 1.19 moles are present in 356.4 g of NiBr3.

Learn more about moles here:

https://brainly.com/question/8455949

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