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0.670 mol of beryllium nitrate, Be(NO3)2 are required for a specific chemical reaction you want to perform in the lab. What mass of Be(NO3)2 do you need to have precisely 0.670 mol of the compound?

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Sagot :

The mass of Be(NO₃)₂ needed to have precisely 0.670 mole of the compound is 89.11 grams

0.670 moles of beryllium nitrate, Be(NO₃)₂ is needed for the chemical reaction. The mass of Be(NO₃)₂ needed to have precisely 0.670 moles of the compound can be calculated as follows:

Molecular mass:

Molecular mass is a number equal to the sum of the atomic masses of the atoms in a molecule.

molecular mass of Be(NO₃)₂  = 9 + 14(2) + 16(6) = 9 + 28 + 96 = 133 grams per mole

Therefore,

1 mole of Be(NO₃)₂ = 133 grams

0.670 moles = ?

cross multiply

mass required = 0.670 × 133

mass of Be(NO₃)₂ required = 89.11 grams

learn more on mass here:https://brainly.com/question/26177156

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