Answered

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Group 1 elements have an average electronegativity of 0.84 (not including hydrogen). Group 17 elements have an average electronegativity of 2.99. These two groups often form bonds. Given this information, which kind of bond will they likely form (ionic or covalent), and what evidence supports your claim? If it is ionic, then include which group gives up its electron to the other group. In three to five sentences, explain your reasoning

Sagot :

okpalawalter8

We have that the Electronegative difference of 2.15 basically makes ionic bonds

Ionic bonds is to be formed

Bonding

Generally, the common electronegativity of the team 1 factors are 0.84 and the common electronegativity of the team 17 factors are 2.99.

Group 17 factors are an awful lot greater electronegative than Group 1 elements.

Group 17 consists of F, Cl, Br and I,Group 1 factor that is Na loses 1 electron from its outermost orbit and varieties Na+ cation.

Group 17 Element that is Cl accepts 1 electron in its outermost orbit and Creates Cl- anion. Now, Na+ cation and Cl- anion combines collectively by using ionic bonds.

Hence, the electronegative difference

(2.99-0.84)=2.15

Electronegative difference of 2.15 basically makes ionic bonds

For more information on Bonding visit

https://brainly.com/question/819068

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