nusratjahanschool
Answered

Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Join our platform to get reliable answers to your questions from a knowledgeable community of experts. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Hi, I am very confused on this higher order thinking question. Can someone please show me the steps to solve this. I DONT NEED AN EXPLANATION, I CAN MAKE MY OWN.

Hi I Am Very Confused On This Higher Order Thinking Question Can Someone Please Show Me The Steps To Solve This I DONT NEED AN EXPLANATION I CAN MAKE MY OWN class=

Sagot :

sqdancefan

Answer:

  9/16 pounds

Step-by-step explanation:

The scale reading is the sum of the container weight and the weight of the cheese. The scale reading and the container weight are given, so the weight of the cheese can be calculated.

  cheese being weighed = scale reading - container weight

  = 1 1/4 - 1/16 = 1 3/16 . . . pounds

__

The additional amount needed is the difference between the desired amount and the weight of the cheese on the scale.

 cheese needed = desired weight - cheese being weighed

  = 1 3/4 -1 3/16 = 9/16 . . . pounds

9/16 pounds of cheese need to be added to the scale.

_____

Additional comment

You can combine the equations:

  cheese needed = desired weight - (scale reading -container weight)

  cheese needed = desired weight - scale reading +container weight

  = 1 3/4 -1 1/4 +1/16 = 9/16 . . . pounds

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.