Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
Answer:
9/16 pounds
Step-by-step explanation:
The scale reading is the sum of the container weight and the weight of the cheese. The scale reading and the container weight are given, so the weight of the cheese can be calculated.
cheese being weighed = scale reading - container weight
= 1 1/4 - 1/16 = 1 3/16 . . . pounds
__
The additional amount needed is the difference between the desired amount and the weight of the cheese on the scale.
cheese needed = desired weight - cheese being weighed
= 1 3/4 -1 3/16 = 9/16 . . . pounds
9/16 pounds of cheese need to be added to the scale.
_____
Additional comment
You can combine the equations:
cheese needed = desired weight - (scale reading -container weight)
cheese needed = desired weight - scale reading +container weight
= 1 3/4 -1 1/4 +1/16 = 9/16 . . . pounds
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.