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Sagot :
It can be deduced that the equilibrium concentration of i− will be 0.053M.
How to calculate the equilibrium concentration
From the information given, the equilibrium constant of the reaction below is kc=0. 25. Since the concentration has also been provided. This will be calculated thus:
[(0.0638 - x)(0.0638 - x)]/x = 0.25
Cross multiply
0.00407 + x² - 0.1276x = 0.25x
x² - 0.3776x + 0.00407 = 0
x = 0.011106M
Therefore, the concentration of I at equilibrium will be:
= 0.0638 - 0.011106
= 0.053M
Therefore, the equilibrium concentration of i− is 0.053M.
Learn more about equilibrium on:
https://brainly.com/question/13414142
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