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solve the linear equations using elimination!!

3a - 2b + 4 =0
2a -5b -1 = 0

Sagot :

Ashrag253

Answer:

A=-2; B=-1

Step-by-step explanation:

3a - 2b + 4 =0

2a -5b -1 = 0

Let's multiple the top equation by 2, and the bottom by -3, and then use addition.

[3a - 2b + 4 =0]*2

[2a -5b -1 = 0]*(-3)

6a-4b+8=0

-6a+15b+3=0

Now add the two equations together:

11b + 11 = 0

Subtract 11 from both sides

11b = -11

Divide both sides by 11

b=-1

Substitute in the first equation:

3a - 2(-1) + 4 = 0

Simplify to get 3a+6 = 0

Subtract 6 from both sides to get 3a = -6

Divide both sides by 3 to get a=-2

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