Answered

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A local university has a student population that is 55% male. 60% of students are undergraduates. 38% are both male and undergraduates. a. What is the probability that a randomly selected student is both female and an undergraduate? b. What is the probability that a randomly selected student is either female or an undergraduate?

Sagot :

ogorwyne

The probability that a randomly selected student is female and an undergraduate = 37%

The probability of being female or an undergraduate= 1.05

The male students

The male population = 55%

Therefore female population would be 1 - 0.55 = 45%

Undergraduates = 60%

The male undergraduate = 38%

Therefore female undergraduates = 60%-38%

= 22%

a. The probability that a randomly selected student is an undergraduate and female

= [tex]\frac{0.22}{0.60}[/tex]

= 37%

B. The probability that the student is female or undergraduate

P(A or B)

= Probability of female = 45/100

Probability of undergraduate = 60/100

= 0.45 + 0.60

= 1.05

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