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Sagot :

Part A

The starting amount of water is 95 cubic meters or m^3 for short. This is the y intercept because it handles the starting amount.

Then the pool is filled at a rate of 4 m^3 per minute. This is the slope, i.e. the rate of change. Because this rate of change is constant, we have a linear equation.

We go from y = mx+b to y = 4x+95

Replace x with t to get the answer.

Answer: 4t + 95

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Part B

Plug in t = 17 and compute

V(t) = 4t + 95

V(17) = 4*17 + 95

V(17) = 163

Answer: 163

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Part C

We go in reverse compared to the previous part.

This time we don't know the t value, but we are given the V(t) value instead.

V(t) = 231

4t+95 = 231

4t = 231-95

4t = 136

t = 136/4

t = 34

Answer: 34

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