Part A
The starting amount of water is 95 cubic meters or m^3 for short. This is the y intercept because it handles the starting amount.
Then the pool is filled at a rate of 4 m^3 per minute. This is the slope, i.e. the rate of change. Because this rate of change is constant, we have a linear equation.
We go from y = mx+b to y = 4x+95
Replace x with t to get the answer.
Answer: 4t + 95
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Part B
Plug in t = 17 and compute
V(t) = 4t + 95
V(17) = 4*17 + 95
V(17) = 163
Answer: 163
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Part C
We go in reverse compared to the previous part.
This time we don't know the t value, but we are given the V(t) value instead.
V(t) = 231
4t+95 = 231
4t = 231-95
4t = 136
t = 136/4
t = 34
Answer: 34
