Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

2. FN) A Fig. 5.6 12 24 x(m) A body is under the action of a force F such that the force-displacement graph of the body is semicircle as shown above. The work done on the body by the force in moving through 24 meters is A. 36J B. 721 JC. 1441 J D. 28871 J
JAMB 1991 Ans: 7211 J or 226.3J 2 Aan 1201​


2 FN A Fig 56 12 24 Xm A Body Is Under The Action Of A Force F Such That The Forcedisplacement Graph Of The Body Is Semicircle As Shown Above The Work Done On T class=

Sagot :

Statement:

A body is under the action of a force F such that the force-displacement graph of the body is semicircle as shown above. The work done on the body by the force in moving through 24 meters.

To find out:

The work done by the body.

Solution:

  • Here force is F and let us consider the displacement as s.
  • We know, work done = Fs.
  • Here the area under the curve is Fs, i.e., work done.
  • We know, area of a semicircle = [tex] \frac{\pi \: {r}^{2} }{2} [/tex]where r is the radius.
  • Here, radius (r) = 24 m
  • Therefore, work done

[tex] = \frac{\pi \: {r}^{2} }{2} \\= \frac{(24) ^{2}\pi }{2} {m}^{2} \\ = \frac{576\pi}{2} {m}^{2} \\ = 288\pi \: {m}^{2} [/tex]

Answer:

The work done is 288π m².

Hope you could understand.

If you have any query, feel free to ask.