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the lateral surface area of a triagular prism is 432cm and height is 18cm the ratio of it sides of base is 3:4:5 find the base sides of prism ?​

Sagot :

Answer:

let the sides of the base be a, b, and C

lateral surface Area =432cm² and h=18cm

SA=0.5ah+0.5bh+0.5ch

432=0.5h(a+b+c) after factorization

432=0.5×18(a+b+c)

432=9(a+b+c)

432/8=a+b+c

48=a+b+c

ratio 3:4:5

total in ratio is 3+4+5=12

48=a+b+c

12=3+4+5

to make twelve equal to 48, multiply by 4

(12=3+4+5)4

48=12+16+20

the side lengths are 12cm,16cm and 20cm

HOPE ITS CLEAR,

PLEASE

MARK BRAINLIEST