[tex]\bold{\huge{\pink{\underline{ Solution}}}}[/tex]
[tex]\bold{\underline{ Given :-}}[/tex]
- A triangle with sides 11m, 13m and 18m
[tex]\bold{\underline{ To \: Find :-}}[/tex]
- We have to check it whether it is right angled triangle or not?
[tex]\bold{\underline{ Let's \: Begin :-}}[/tex]
[tex]\sf{\red{ In \:right \:angled\ : triangle, }}[/tex]
According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.
We imply it in the given triangle ,
[tex]\sf{\red{ ( Perpendicular)² + (Base)² = (Hypotenuse)²}}[/tex]
[tex]\sf{(AB)² + (BC)² = (AC)²}[/tex]
[tex]\sf{ (11)² + (13)² = (18)² }[/tex]
[tex]\sf{ 121 + 169 ≠ 324 }[/tex]
[tex]\sf{ 290 ≠ 324 }[/tex]
From Above we can conclude that,
The sum of the squares of two small sides that is perpendicular height and base is not equal to the square of longest side that is Hypotenuse
[tex]\sf{\blue{ Hence,\: Your\: answer \:is \:false }}[/tex]
