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Solve the quadratic equation 3x²-3x-1=0?
(by using the square method)​

Sagot :

Answer:

x=1 and x=-1/3

Step-by-step explanation:

[tex]3x^2-2x-1=0\\\\3(x^2-\frac{2}{3}x-\frac{1}{3})=0\\ \\3(x^2-\frac{2}{3}x-\frac{1}{3}+\frac{4}{9})=3(\frac{4}{9})\\ \\ 3(x^2-\frac{2}{3}x+\frac{1}{9})=\frac{4}{3}\\ \\ 3(x-\frac{1}{3})^2=\frac{4}{3}\\ \\(x-\frac{1}{3})^2=\frac{4}{9}\\ \\x-\frac{1}{3}=\pm\frac{2}{3}[/tex]

[tex]x-\frac{1}{3}=\frac{2}{3}\\ \\x=\frac{3}{3}\\ \\x=1[/tex]

[tex]x-\frac{1}{3}=-\frac{2}{3}\\ \\x=-\frac{1}{3}[/tex]

Therefore, x=1 and x=-1/3

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