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The means and mean absolute deviations of the individual times of members on two 4 times 400 meter relay track teams are shown in the table below. Means and Mean Absolute Deviations of Individual Times of Members of 4 times 400 meter Relay Track Teams Team A Team B Mean 59. 32 s 59. 1 s Mean Absolute Deviation 1. 5 s 2. 4 s What percent of Team B’s mean absolute deviation is the difference in the means? 9% 15% 25% 65%.

Sagot :

Percentage is a way to show the part of a whole. The percent of Team B’s mean absolute deviation is the difference in the means is 9%.

What is the percentage?

The percentage is a way to show a part of a whole. for example, one-fourth of area A can be written like 25% of A(0.25A.)

Given to us

Mean and Mean Absolute Deviation of Team A: 59.32 sec, 1.5 sec

Mean and Mean Absolute Deviation of Team B: 59.1 sec, 2.4 sec


As it is given in the problem we need to find the percent of Team B’s mean absolute deviation is the difference in the means, therefore,

[tex]Percentage = \dfrac{\text{Mean of Team A - Mean of Team B}}{\text{Mean Absolute Deviation of Team B}} \times 100[/tex]

Substitute the values,

[tex]Percentage = \dfrac{59.32 - 59.10}{2.4}\times 100 = 9.166\% \approx 9\%[/tex]

Hence, the percent of Team B’s mean absolute deviation is the difference in the means is 9%.

Learn more about Percentage:

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