Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Percentage is a way to show the part of a whole. The percent of Team B’s mean absolute deviation is the difference in the means is 9%.
What is the percentage?
The percentage is a way to show a part of a whole. for example, one-fourth of area A can be written like 25% of A(0.25A.)
Given to us
Mean and Mean Absolute Deviation of Team A: 59.32 sec, 1.5 sec
Mean and Mean Absolute Deviation of Team B: 59.1 sec, 2.4 sec
As it is given in the problem we need to find the percent of Team B’s mean absolute deviation is the difference in the means, therefore,
[tex]Percentage = \dfrac{\text{Mean of Team A - Mean of Team B}}{\text{Mean Absolute Deviation of Team B}} \times 100[/tex]
Substitute the values,
[tex]Percentage = \dfrac{59.32 - 59.10}{2.4}\times 100 = 9.166\% \approx 9\%[/tex]
Hence, the percent of Team B’s mean absolute deviation is the difference in the means is 9%.
Learn more about Percentage:
https://brainly.com/question/8011401
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.