Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

What must the charge (sign and magnitude) of a particle of mass 1.44 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 680 N/C

Sagot :

Answer:

Q E = m g      electric and gravitational forces balance - both E and g are taken as positive in the downward direction

Q = m g / E = .00144 kg * 9.8 m/s^2 / 680 N/C = 2.08E-5 coul

This is the charge required for the specified force

Therefore Q = -2.08-5 C      for the charge to remain stationary

Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.