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The world’s largest chandelier was created by a company in South Korea
and hangs in one of the department stores in Seoul, South Korea. The
chandelier’s mass is about 9700 kg. Consider a situation in which this
chandelier is placed in a wooden crate whose mass is negligible. The
chandelier is then pulled along a smooth horizontal surface by two forces
that are parallel to the smooth surface, are at right angles to each other,
and are applied 45º to either side of the direction in which the chandelier is
moving. If each of these forces is 1200 N, how much work must be done on
the chandelier to pull it 12 m?

Sagot :

onyebuchinnaji

The work done by the two forces in moving the chandelier to the given distance is 5,091.2 J.

Work done by a single force on the chandelier

The work done by a single force on the chandelier is determined by taking the net horizontal force applied on the chandelier over the given distance.

[tex]W = (F - F_f) d\\\\W = (F sin\theta \ - \ F_f)d[/tex]

where;

[tex]F_f[/tex] is frictional force = 0 (smooth surface).

[tex]W = Fsin(\theta) d\\\\W = 1200 \times sin(45) \times 12\\\\W = 10,182.34 \ J[/tex]

Work done by the two forces

When the two forces combine to pull the chandelier, the total work done will be shared by the two forces.

[tex]W_1 = W_2 = \frac{10,182.34}{2} = 5,091.2 \ J[/tex]

Thus, the work done by the two forces in moving the chandelier to the given distance is 5,091.2 J.

Learn more about work done here: https://brainly.com/question/8119756

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