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Sagot :
The work done by the two forces in moving the chandelier to the given distance is 5,091.2 J.
Work done by a single force on the chandelier
The work done by a single force on the chandelier is determined by taking the net horizontal force applied on the chandelier over the given distance.
[tex]W = (F - F_f) d\\\\W = (F sin\theta \ - \ F_f)d[/tex]
where;
[tex]F_f[/tex] is frictional force = 0 (smooth surface).
[tex]W = Fsin(\theta) d\\\\W = 1200 \times sin(45) \times 12\\\\W = 10,182.34 \ J[/tex]
Work done by the two forces
When the two forces combine to pull the chandelier, the total work done will be shared by the two forces.
[tex]W_1 = W_2 = \frac{10,182.34}{2} = 5,091.2 \ J[/tex]
Thus, the work done by the two forces in moving the chandelier to the given distance is 5,091.2 J.
Learn more about work done here: https://brainly.com/question/8119756
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