Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Determine whether the improper integral converges or diverges, and find the value of each that converges.

Sagot :

Integration is the process of finding integral. The value of the integration [tex]\int_{{{0}}}^{{\infty}}}{\dfrac{{{\left.{d}{x}\right.}}}{{{\left({x}+{9}\right)}^{{{2}}}}}}\)\\[/tex] converges.

What is integration?

Integration is the process of finding integral. Integral help us to describe the function of area, volume, and other such concepts.

Given to us

[tex]\int_{{{0}}}^{{\infty}}}{\dfrac{{{\left.{d}{x}\right.}}}{{{\left({x}+{9}\right)}^{{{2}}}}}}\)\\[/tex]

To know whether the internal will converge or diverge, we will solve the integral,

[tex]\int_{{{0}}}^{{\infty}}}{\dfrac{{{\left.{d}{x}\right.}}}{{{\left({x}+{9}\right)}^{{{2}}}}}}\)\\\\\\ =[ -\dfrac{1}{x+9}]_0^\infty\\\\= \dfrac{1}{9}\\\\= 0.\overline{1}[/tex]

As we can see that the value of the integration [tex]\int_{{{0}}}^{{\infty}}}{\dfrac{{{\left.{d}{x}\right.}}}{{{\left({x}+{9}\right)}^{{{2}}}}}}\)\\[/tex] converges toward zero, therefore we can say that the given integration converges.

Hence, the value of the integration [tex]\int_{{{0}}}^{{\infty}}}{\dfrac{{{\left.{d}{x}\right.}}}{{{\left({x}+{9}\right)}^{{{2}}}}}}\)\\[/tex] converges.

Learn more about Integration:

https://brainly.com/question/18651211