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if i initially have a gas with a pressure or 84.0kPa and a temperature of 35.0 C and i heat it to 230 C, what will the new pressure be? Assume the volume of the container is constant

Sagot :

The new pressure would be 552kPa

Calculate the pressure of a gas

Using the formula below

[tex] \frac{p1v1}{t1} = \frac{p2v2}{t2} [/tex]

But new pressure is = P2.

Also volume is constant

From the formula above, make P2 the subject of formula;

[tex]p2 = \frac{p1v1t2}{t1v2} [/tex]

But P1 = 84kPa

T1 = 35°C

T2 =230°C

V1= V2

[tex]p2 = \frac{84 \times 230}{35} [/tex]

[tex]p2 = \frac{19320}{35} [/tex]

P2 = 552kPa

Therefore, new pressure would be 552kPa

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