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Find an equation of the line with gradient 2/3 and that passes through the point (-1, -3)

Sagot :

Lanuel

An equation of the line with the given gradient and points is [tex]y=\frac{2x}{3} -\frac{7}{3}[/tex]

Given the following data:

  • Gradient or slope = [tex]\frac{2}{3}[/tex]
  • Points on x-axis = -1
  • Points on y-axis = -3.

To find an equation of the line with the given gradient and points:

How to calculate an equation of a line.

Mathematically, the equation of a line is given by this formula:

[tex]y-y_1 =m(x-x_1)[/tex]

Where:

  • m is the gradient or slope.
  • y is the point on the horizontal axis.
  • x is the point on the vertical axis.

Substituting the given parameters into the formula, we have;

[tex]y-(-3) =\frac{2}{3} (x-[-1])\\\\y+3=\frac{2}{3} (x+1)\\\\3y+9=2x+2\\\\3y=2x+2-9\\\\3y=2x-7\\\\y=\frac{2x}{3} -\frac{7}{3}[/tex]

Read more on gradient here: https://brainly.com/question/26044936

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