Answered

Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Explore thousands of questions and answers from a knowledgeable community of experts ready to help you find solutions. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

Find an equation of the line with gradient 2/3 and that passes through the point (-1, -3)

Sagot :

Lanuel

An equation of the line with the given gradient and points is [tex]y=\frac{2x}{3} -\frac{7}{3}[/tex]

Given the following data:

  • Gradient or slope = [tex]\frac{2}{3}[/tex]
  • Points on x-axis = -1
  • Points on y-axis = -3.

To find an equation of the line with the given gradient and points:

How to calculate an equation of a line.

Mathematically, the equation of a line is given by this formula:

[tex]y-y_1 =m(x-x_1)[/tex]

Where:

  • m is the gradient or slope.
  • y is the point on the horizontal axis.
  • x is the point on the vertical axis.

Substituting the given parameters into the formula, we have;

[tex]y-(-3) =\frac{2}{3} (x-[-1])\\\\y+3=\frac{2}{3} (x+1)\\\\3y+9=2x+2\\\\3y=2x+2-9\\\\3y=2x-7\\\\y=\frac{2x}{3} -\frac{7}{3}[/tex]

Read more on gradient here: https://brainly.com/question/26044936

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.