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You have 7.86 x 10^23 molecules of NaCl. This would be equal to ___ grams of NaCl.

Sagot :

[tex]7.86 \times 10 {}^{23} atoms \\ \frac{7.86}{6.022} \times \frac{10 {}^{23} }{ {10}^{23} } = 1.305\: moles[/tex]

1.305 × (23+35.5) = 76.34 grams

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