Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

PLEASE HELP

Quinton and Reema were both selling cupcakes to raise money for
their school's math club. They both sold 3 cupcakes. Who earned
more for each cupcake?




PLEASE HELP Quinton And Reema Were Both Selling Cupcakes To Raise Money For Their Schools Math Club They Both Sold 3 Cupcakes Who Earned More For Each Cupcake class=

Sagot :

Answer: Answer

3.0/5

26

rani01654

Ace

2.6K answers

13.7M people helped

Answer:

C = 75 + 0.17x and R = 2x

2x - (75 + 0.17x) > 0

x ≥ 41

Step-by-step explanation:

The cost to make the cupcakes is a fixed $75 plus $0.17 per cupcakes made and the selling price of each cupcake is $2.00.

Part A: Now, the equation for the cost, C, for making x cupcakes is  

C = 75 + 0.17x ......... (1)

Again the equation for the revenue, R, from selling x cupcakes is

R = 2x ............ (2)

Part B: So, the inequality that could be solved to find the number of cupcakes, x, that must be made and sold to make a profit is  

R - C > 0

2x - (75 + 0.17x) > 0 ......... (3)

Part C: Solving inequality (3) we get

(2 - 0.17)x > 75

⇒ x > 40.98

⇒ x ≥ 41 {Since, x can not be a fraction}

(Answer)