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Arithmetic sequence a1=8 d=9

Sagot :

Answer:

[tex]\ \ \ \ \ \ a_n=8+9(n-1)\\\implies a_n=8+9n-9\\\implies a_n=9n-1[/tex]

Step-by-step explanation:

arithmetic sequence equation:

[tex]a_n=a+(n-1)d[/tex]

where a is the first term and d is the common difference

Therefore,

[tex]\ \ \ \ \ \ a_n=8+9(n-1)\\\implies a_n=8+9n-9\\\implies a_n=9n-1[/tex]