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If the surface is initially completely covered with n -butane at 150 K , how long will it take for 25% of the molecules to desorb (leave the surface)

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pstnonsonjoku

The time taken or 25% of the molecules to desorb is 2.2 seconds

What is a first order reaction?

A first order reaction is one in which the rate of reaction depends on the concentration of a single specie.

Since;

t1/2 = 0.693/k =  0.693/ 0.128 s-1

t1/2 = 5.4 secs

Using the formula;

0.693/t1/2 = 2.303/t log (No/N)

0.693/5.4 = 2.303/t log 1/0.75

0.693/5.4 = 2.303/t log

0.693/5.4 = 0.287/t

t =  2.2 seconds

Learn more about first order reaction: https://brainly.com/question/12446045

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