Answered

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Solve for X
3(x + 7) < 7(x + 2)

Sagot :

semsee45

Answer:

x > 7/4

Step-by-step explanation:

3(x + 7) < 7(x + 2)

Expand brackets:                 3x + 21 < 7x + 14

Subtract 14 from both sides:  3x +7 < 7x

Subtract 3x from both sides:         7 < 4x

Divide both sides by 4:              7/4 < x

Therefore x > 7/4

[tex]\\ \tt\hookrightarrow 3(x+7)<7(x+2)[/tex]

[tex]\\ \tt\hookrightarrow 3x+21<7x+14[/tex]

[tex]\\ \tt\hookrightarrow 3x-7x<14-21[/tex]

[tex]\\ \tt\hookrightarrow -4x<-7[/tex]

[tex]\\ \tt\hookrightarrow 4x>7[/tex]

[tex]\\ \tt\hookrightarrow x>7/4[/tex]

[tex]\\ \tt\hookrightarrow x\in(\dfrac{7}{4},\infty)[/tex]

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